The mass of a penny was measured six times. The following data was reported: 9.314 g, 9.215 g, 9.323 8 8.103 g, 9.278 g, and 9.344 g. 5. (a) Should any data be excluded in calculating the average mass of the penny? (b) Calculate the average value of the mass of the penny, excluding unreasonable value (c) Calculate the average deviation from the mean.

Answer:a) 8.103 gb) 9.2948c) 0Step-by-step explanation:Given:Data reported:9.314 g, 9.215 g, 9.323 g, 8.103 g, 9.278 g, and 9.344 gNow,All the values except the 8.103 are above 9Here the data 8.103 varies very much with respect to the other valuesHence, a) the data 8.103 should be excludedb) average value of the mass of the penny = [tex]\frac{9.314 + 9.215 + 9.323 + 9.278 + 9.344 }{5}[/tex]= 9.2948 gc) Deviation = Mean - Data9.2948 - 9.314 = -0.01929.2948 - 9.215 = 0.07989.2948 - 9.323 = -0.02829.2948 - 9.278 = 0.01689.2948 - 9.344 = -0.0492Thus,Average deviation from mean = tex]\frac{-0.0192 + 0.0798 -0.0282 + 0.0168 -0.0492 }{5}[/tex]= 0